How do you write the slope-intercept equation of a line containing (4, -1) and with a slope of 3/5?

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Answer 1 · 2017-08-22T22:48:50

#y = 3/5x -17/5" " or" " y = 3/5x -3 2/5#

# y = mx + b " "# with #" "m = 3/5 " "y = -1 " "x = 4 #

substituting and solving for b gives

# -1 = (3/5) 4+ b " "# this gives

# -1 = 12/5 + b " "# subtracting # 12/5 # from both sides gives

# -1 - 12/5 = b" "# This gives

# - 17/5 = b# so the slope intercept form would be

# y = 3/5 x -17/5 #