Question

How do you write the slope intercept form of the line `13x-11y=-12`?

Answer 1

`y=13/11x+12/11`

Explanation:

`"the equation of a line in "color(blue)"slope-intercept form"` is.

`•color(white)(x)y=mx+b`

`"rearrange "13x-11y=-12" into this form"`

`"subtract "13x" from both sides"`

`cancel(13x)cancel(-13x)-11y=-13x-12`

`rArr-11y=-13x-12`

`"multiply through by "-1`

`11y=13x+12`

`"divide all terms by 11"`

`rArry=13/11x+12/11larrcolor(red)"in slope-intercept form"`

Answer 2

`y=13/11x+12/11`

Explanation:

The first step is to re-arrange the equation such that `y` and its coefficients are alone:

`cancel(13x)-11ycolor(red)(cancel(-13x))=-12color(red)(-13x)`

`-11y=-13x-12`

Next, divide through by `y`'s coefficient, and you will have slope-intercept form:

`(cancel(-11)y)/color(red)(cancel(-11))=(cancel(-)13x)/color(red)(cancel(-)11)+(cancel(-)12)/color(red)(cancel(-)11)`

`color(green)(y=13/11x+12/11)`