How do you write the slope intercept form of the line #3x-2y=-16#?

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Answer 1 · 2017-05-21T00:03:34

#y = 3/2x + 8#

Simply make y the subject of the equation:

#-2y = -16 - 3x#

#y = 8 + 3/2x#

#y = 3/2x + 8#

Answer 2 · 2017-05-21T00:04:04

#y=3/2x+8#

Slope intercept form is defined as #y=mx+b# where #m# is the slope an #b# is the #y#-intercept.

In this case we have #3x-2y=-16#. To write this in slope intercept form we must solve for #y#. Thus,

Subtract #3x# to both sides:

#cancel(3x-3x)-2y=-3x-16#

#-2y=-3x-16#

Divide #-2# to both sides:

#cancel(-2/-2)y=(-3x-16)/-2#

Simplify:

#y=3/2x+8#

This is now written in slope intercept form where #m# (the slope) is #3/2# and our #y#-intercept is #8#