How do you write the standard form of a line given (-2, 4) and has a slope of 1/2?

2 Answers
Aug 15, 2016

#y=x/2+5#

Explanation:

#m:"slope of line"#
#P:(x,y)"any point of line"#

#"the standard line equation is "y-y_1=m(x-x_1)#

#"given " m=1/2" ; "P(-2,4)" ; "y_1=4" ; "x_1=-2#

#y-4=1/2(x+2)#

#y-4=x/2+1#

#y=x/2+1+4#

#y=x/2+5#

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Aug 15, 2016

#y=1/2x+5#

Explanation:

The equation of a line in #color(blue)"point-slope form"# is.

#color(red)(|bar(ul(color(white)(a/a)color(black)(y-y_1=m(x-x_1))color(white)(a/a)|)))#
where m represents the slope and #(x_1,y_1)" a point on the line"#

here #m=1/2" and " (x_1,y_1)=(-2,4)#

substitute these values into the equation.

#rArry-4=1/2(x+2)#

distribute the bracket and collect 'like terms'

#y-4=1/2x+1rArry=1/2x+5" is the equation"#