How do you write the standard form of a line given (-3, -10) and has a slope of 2?

1 Answer
Feb 5, 2017

#color(red)(2)x - color(blue)(1)y = color(green)(4)#

Explanation:

First, use the point-slope formula to write an equation for the line. The point-slope formula states: #(y - color(red)(y_1)) = color(blue)(m)(x - color(red)(x_1))#

Where #color(blue)(m)# is the slope and #color(red)(((x_1, y_1)))# is a point the line passes through.

Substituting the information from the problem gives:

#(y - color(red)(-10)) = color(blue)(2)(x - color(red)(-3))#

#(y + color(red)(10)) = color(blue)(2)(x + color(red)(3))#

The standard form of a linear equation is: #color(red)(A)x + color(blue)(B)y = color(green)(C)#

where, if at all possible, #color(red)(A)#, #color(blue)(B)#, and #color(green)(C)#are integers, and A is non-negative, and, A, B, and C have no common factors other than 1

Transform the equation from point-slope to standard form as follows:

#y + color(red)(10) = (color(blue)(2) xx x) + (color(blue)(2) xx color(red)(3))#

#y + color(red)(10) = 2x + 6#

#-color(red)(2x) + y + color(red)(10) - 10 = -color(red)(2x) + 2x + 6 - 10#

#-color(red)(2x) + y + 0 = 0 - 4#

#-2x + y = -4#

#-1(-2x + y) = -1 xx -4#

#2x - y = 4#