How do you write the standard form of a line given (–3, 4) with a slope of 2?

1 Answer
Mar 20, 2017

#2x-y=-10#

Explanation:

The first step is to establish the equation of the line.

The equation of a line in #color(blue)"point-slope form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(y-y_1=m(x-x_1))color(white)(2/2)|)))#
where m represents the slope and # (x_1,y_1)" a point on the line."#

#"here " m=2" and " (x_1,y_1)=(-3,4)#

#y-4=2(x-(-3))#

#rArry-4=2(x+3)larrcolor(red)" in point-slope form"#

The equation of a line in #color(blue)"standard form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(Ax+By=C)color(white)(2/2)|)))#
where A is a positive integer and B, C are integers.

#"Rearrange " y-4=2(x+3)" into this form"#

#y-4=2x+6#

#rArr2x-y=-10larrcolor(red)" in standard form"#