Question

How do you write the standard form of a line given (–3, 4) with a slope of 2?

Answer 1

`2x-y=-10`

Explanation:

The first step is to establish the equation of the line.

The equation of a line in `color(blue)"point-slope form"` is.

`color(red)(bar(ul(|color(white)(2/2)color(black)(y-y_1=m(x-x_1))color(white)(2/2)|)))`
where m represents the slope and `(x_1,y_1)" a point on the line."`

`"here " m=2" and " (x_1,y_1)=(-3,4)`

`y-4=2(x-(-3))`

`rArry-4=2(x+3)larrcolor(red)" in point-slope form"`

The equation of a line in `color(blue)"standard form"` is.

`color(red)(bar(ul(|color(white)(2/2)color(black)(Ax+By=C)color(white)(2/2)|)))`
where A is a positive integer and B, C are integers.

`"Rearrange " y-4=2(x+3)" into this form"`

`y-4=2x+6`

`rArr2x-y=-10larrcolor(red)" in standard form"`