# How do you write the standard form of a line given (6, -4) and is parallel to the line 5x-5y=2?

Jun 27, 2017

$x - y = 10$

#### Explanation:

$A x + B y = C$ => Equation of line in standard form, slope = -B/A:
$5 x - 5 y = 2$
$s l o p e m = - \frac{- 5}{5} = 1$
Start with point slope formula: in this case m = 1 , point(6, -4):
$y - {y}_{1} = m \left(x - {x}_{1}\right)$
$y - \left(- 4\right) = 1 \left(x - 6\right)$
$y + 4 = x - 6$
$x - y = 10$ => the required line in standard form.