Question

How do you write the standard form of a line given (6, -4) and is parallel to the line 5x-5y=2?

Answer 1

`x-y=10`

Explanation:

`Ax+By=C` => Equation of line in standard form, slope = -B/A:
`5x-5y=2`
`slope m=-(-5)/5 = 1`
Start with point slope formula: in this case m = 1 , point(6, -4):
`y-y_1=m(x-x_1)`
`y-(-4)=1(x-6)`
`y+4=x-6`
`x-y=10` => the required line in standard form.