How do you write the standard form of a line given (-6,-5) and has slope -2?

1 Answer
Jan 22, 2017

See the entire solution process below:

Explanation:

First, because we are given a point and the slope we can find an equation using the point-slope formula.

The point-slope formula states: #(y - color(red)(y_1)) = color(blue)(m)(x - color(red)(x_1))#

Where #color(blue)(m)# is the slope and #color(red)(((x_1, y_1)))# is a point the line passes through.

Substituting the values from the problem gives:

#(y - color(red)(-5)) = color(blue)(-2)(x - color(red)(-6))#

#(y + color(red)(5)) = color(blue)(-2)(x + color(red)(6))#

The standard form of a linear equation is:

#color(red)(A)x + color(blue)(B)y = color(green)(C)#

where, if at all possible, #color(red)(A)#, #color(blue)(B)#, and #color(green)(C)#are integers, and A is non-negative, and, A, B, and C have no common factors other than 1

We can now transform our equation into this format.

#y + color(red)(5) = (color(blue)(-2) xx x) + (color(blue)(-2) xx color(red)(6))#

#y + color(red)(5) = -2x - 12#

#y + color(red)(5) - 5 + color(blue)(2x) = -2x - 12 - 5 + color(blue)(2x)#

#y + color(red)(5) - 5 + color(blue)(2x) = -2x - 12 - 5 + color(blue)(2x)#

#2x + y + 0 = 0 - 17#

#color(red)(2)x + color(blue)(1)y = color(green)(-17)#