# How do you write the standard form of a line given (6, -8), m = -2?

$2 x + y - 4 = 0.$
Given a point (pt.) $\left({x}_{1} , {y}_{1}\right)$ on line with slope $= m$, its eqn. is $\left(y - {y}_{1}\right) = m \left(x - {x}_{1}\right) .$
In our case, it is, $\left(y + 8\right) = - 2 \left(x - 6\right) = - 2 x + 12 ,$ i.e., $2 x + y - 4 = 0.$