Question

How do you write the standard form of a line given (6, -8), m = -2?

Answer 1

`2x+y-4=0.`

Explanation:

Given a point (pt.) `(x_1,y_1)` on line with slope `=m`, its eqn. is `(y-y_1)=m(x-x_1).`
In our case, it is, `(y+8)=-2(x-6)=-2x+12,` i.e., `2x+y-4=0.`