# How do you write the standard form of a line given slope= 4/5, passes through (10, -3)?

##### 1 Answer

#### Explanation:

The equation of a line in

#color(blue)"slope-intercept form"# is

#color(red)(|bar(ul(color(white)(a/a)color(black)(y=mx+b)color(white)(a/a)|)))#

where m represents the slope and b , the y-intercept.here

#m=4/5#

Partial equationis :#y=4/5x+b# To find b , use the point (10 ,-3) that the line passes through.

x = 10 , y = -3 and substitute into Partial equation.

#4/cancel(5)^1 xxcancel(10)^2+b=-3rArrb=-3-8=-11#

#rArrcolor(red)(|bar(ul(color(white)(a/a)color(black)(y=4/5x-11)color(white)(a/a)|)))" is the equation"# If we multiply both sides by 5 to eliminate the fraction.

#5y=4/cancel(5)^1 xxcancel(5)^1 x-(11xx5)#

#rArr5y=x-55# and

#color(red)(|bar(ul(color(white)(a/a)color(black)(5y-x+55=0)color(white)(a/a)|)))" is another form of the equation"#