Question

How do you write the standard form of a line given slope= -5, passes through (-3, -8)?

Answer 1

`y=-5x-23`

Explanation:

The equation of a line in `color(blue)"point-slope form"` is

`color(red)(|bar(ul(color(white)(a/a)color(black)(y-y_1=m(x-x_1))color(white)(a/a)|)))`
where m represents the slope and `(x_1,y_1)" a point on the line"`

here m = - 5 and `(x_1,y_1)=(-3,-8)`

substitute these values into the equation.

`rArry-(-8)=-5(x-(-3))rArry+8=-5(x+3)`

distribute bracket and collect 'like terms'

`rArry+8=-5x-15rArry=-5x-23`