How do you write the standard form of the equation given (-1,2) and slope 2?

1 Answer
Jan 7, 2018

#2x-1y=-4#

Explanation:

Given the point #(color(red)(hatx),color(blue)(haty))=(color(red)(-1),color(blue)2)# and a slope of #color(green)m=color(green)2#

the *slope-point form is:
#y-color(blue)(haty)=color(green)m(x-color(red)(hatx))#
#rarrcolor(white)("xxxx")y-color(blue)(2)=color(green)2(x-color(red)(""(-1)))#

We wish to convert this into standard form
#Ax+By=C# with #A,B,C in ZZ, A>=0#

Simplifying our slope-point form
#color(white)("XXX")y-2=2x+2#
Exchanging left and right sides
#color(white)("XXX")2x+2=y-2#
Subtracting #1y# from both sides:
#color(white)("XXX")2x-1y+2=-2#
Subtracting #2# from both sides:
#color(white)("XXX")2x-1y=-4#
(which is standrd form)