# How do you write the standard form of the equation of the circle with center (0,0) R=6?

Jun 22, 2018

${x}^{2} + {y}^{2} = 36$

#### Explanation:

If you know the coordinates of the center $\left({x}_{0} , {y}_{0}\right)$ and the radius $r$ of a circle, the equation is

${\left(x - {x}_{0}\right)}^{2} + {\left(y - {y}_{0}\right)}^{2} = {r}^{2}$

In your case, the center is $\left({x}_{0} , {y}_{0}\right) = \left(0 , 0\right)$ and the radius is $r = 6$. So, the equation is

${\left(x - 0\right)}^{2} + {\left(y - 0\right)}^{2} = {6}^{2}$

which you can rewrite as

${x}^{2} + {y}^{2} = 36$