How do you write this expression in radical form (x^2)^(4/3)?

${\left({x}^{2}\right)}^{\frac{4}{3}} = {\sqrt[3]{x}}^{8}$
As ${\left({a}^{m}\right)}^{n} = {a}^{m n}$, ${\left({x}^{2}\right)}^{\frac{4}{3}} = {x}^{2 \times \frac{4}{3}} = {x}^{\frac{8}{3}}$
Now, in radical form ${a}^{\frac{1}{p}} = \sqrt[p]{a}$
Hence ${x}^{\frac{8}{3}} = {\left({x}^{8}\right)}^{\frac{1}{3}} = {\sqrt[3]{x}}^{8}$