How do you write #x^2-13x+12# in factored form?

1 Answer
Apr 25, 2018

Answer:

#x^2-13x+12=color(red)((x-1)(x-12))#

Explanation:

Remember
#color(white)("XXX")(x+color(blue)a) * (x+color(lime)b))=x^2+(color(blue)a+color(lime)b)x+color(blue)acolor(lime)b#

So we are looking for two values, #color(blue)a# and #color(lime)b#, such that
#color(white)("XXX")color(blue)a+color(lime)b=-13#
and
#color(white)("XXX")color(blue)a * color(lime)b = 12#