# How do you write (x^2-9) / ( |x+3| ) as a piecewise function?

$f \left(x\right) = x - 3$ if $x > - 3$ and $f \left(x\right) = - \left(x - 3\right)$ if $x < - 3$
$\frac{x + 3}{|} x + 3 | = 1$ if $x > - 3$
$\frac{x + 3}{|} x + 3 | = - 1$ if $x < - 3$