How do you write #x-2y-2=0# into slope intercept form?
1 Answer
Aug 22, 2015
Explanation:
The equation of a line in slope-intercept form looks like this
#color(blue)(y = mx + b)" "# , where
In your case, you have all the terms on one side of the equation. This means that you can write the equation in slope-intercept form by moving the
This will get you
#x - color(red)(cancel(color(black)(2y))) + color(red)(cancel(color(black)(2y))) - 2 = 2y#
#x - 2 = 2y#
#1/2x - 2/2 = (color(red)(cancel(color(black)(2))) * y)/color(red)(cancel(color(black)(2)))#
The slope-intercept form for your line will be
#color(green)(y = 1/2x - 1)#