How do you write #x-2y-2=0# into slope intercept form?

1 Answer
Aug 22, 2015

Answer:

#y = 1/2x - 1#

Explanation:

The equation of a line in slope-intercept form looks like this

#color(blue)(y = mx + b)" "#, where

#m# - the slope of the line;
#b# - the #y#-intercept.

In your case, you have all the terms on one side of the equation. This means that you can write the equation in slope-intercept form by moving the #y#-term to the other side of the equation, the dividing all the terms by #2#.

This will get you

#x - color(red)(cancel(color(black)(2y))) + color(red)(cancel(color(black)(2y))) - 2 = 2y#

#x - 2 = 2y#

#1/2x - 2/2 = (color(red)(cancel(color(black)(2))) * y)/color(red)(cancel(color(black)(2)))#

The slope-intercept form for your line will be

#color(green)(y = 1/2x - 1)#