How do you write #(x-5)(x+2)# in standard form?
Each term in the 2nd bracket must be multiplied by each term in the 1st. This can be done as follows.
#color(blue)"x" (x + 2 )color(blue)"-5"(x + 2 ) = x^2 + 2x - 5x - 10 #
now collect like terms
# rArr (x - 5 )(x + 2 ) = x^2 - 3x - 10 " is in standard form "#
Writing an answer in standard form means , start with the term that has the highest power of the variable,
#" in this case " x^2 #followed by terms with decreasing powers until the last term, usually a constant.