How is the graph of #h(x)=1.35x^2+2.6# related to the graph of #f(x)=x^2#?

1 Answer
Dwight
Apr 26, 2017

Both are parabolas, but #h(x)# opens more rapidly and has a different vertex. Details follow...

Explanation:

The coefficient 1.35 causes the parabola #h(x)# to open more rapidly - the graph is "slimmer".

The constant term 2.6 causes the vertex of the graph to move upward. Instead of being located at #y=0#, it is located at #y=2.6# (but still at #x=0# in both cases).

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