How is the graph of #h(x)=1.35x^2+2.6# related to the graph of #f(x)=x^2#?

1 Answer
Dwight
Apr 26, 2017

Both are parabolas, but #h(x)# opens more rapidly and has a different vertex. Details follow...

Explanation:

The coefficient 1.35 causes the parabola #h(x)# to open more rapidly - the graph is "slimmer".

The constant term 2.6 causes the vertex of the graph to move upward. Instead of being located at #y=0#, it is located at #y=2.6# (but still at #x=0# in both cases).

Related questions
See all questions in Quadratic Functions and Their Graphs
Impact of this question
798 views around the world
You can reuse this answer
Creative Commons License