How is the graph of #y=-1/3x^2-4# related to the graph of #f(x)=x^2#?

1 Answer
Tony B
Feb 17, 2017

See explanantion

Explanation:

#color(blue)(1->)#The general shape of the graph #y=x^2 # is that of #uu#

#color(blue)(2->)#The -4 lowers the graph of #y=x^2# by 4

#color(blue)(3->)#Putting a minus sign in front of the #x^2# so that we have #y=-x^2-4# turns the whole thing upside. Now we have the general shape #nn#

#color(blue)(4->)#the #1/3# in #y=-1/3x-4# has the effect of widening the graph

Tony B

Related questions
See all questions in Quadratic Functions and Their Graphs
Impact of this question
4453 views around the world
You can reuse this answer
Creative Commons License