Question

How many complex roots does 6x^5 + x^4 - 3 = 0 have?

Answer 1

See below.

Explanation:

The functions

`f(x) = x^4`

and

`g(x) = 1/(2x+1/6)`

have only a intersection point in the first quadrant hence `6x^5+x^4-3=0` has four (4) complex conjugate roots.