# How many f orbitals are present in n=3?

##### 1 Answer

Zero.

#### Explanation:

As you know, the number of **orbitals** you get **per energy shell** is given by the equation

#color(blue)("no. of orbitals" = n^2)" "# , where

Now, the third energy level, characterized by **a total** of

#"no. of orbitals" = 3^2 = 9#

orbitals. But how many of these orbitals will be **f-orbitals**?

As it turns out, none.

Each energy level contains a number of **subshells** given by the *angular momentum quantum number*,

#l = 0, 1, 2, ..., n-1#

This means that the third energy level will have a total of **three subshells**

one s-subshell, for which#l=0# one p-subshell, for which#l=1# one d-subshell, for which#l=2#

The **f-subshell**, for which *fourth energy level*,

Therefore, you can say that the third energy level **contains no f-orbitals** since it contains no *f-subhsell*.