How many geometric isomers exist for the molecule #CH_3-CH=CH-CH=CH-CH_3#?

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Answer 1 · 2016-09-23T17:50:42

There are three geometric isomers of hexa-2,4-diene.

The four possibilities are #(E,E)#, #(E,Z)#, #(Z,E)#, and #(Z,Z)#.

However, #(E,Z)#and #(Z,E)# are identical.

#(2E,4E)"-hexa-2,4-diene"#

(2E,4E)-hexa-2,4-diene#

#(2E,4Z)"-hexa-2-4-diene"#

(2E,4Z)-hexa-2-4-diene

#(2Z,4Z)"-hexa-2-4-diene"#

(2Z,4Z)-hexa-2-4-diene