How many grams of #CO_2# are produced when 88 g of #O_2# are reacted with an excess of ethane?

1 Answer
Jun 24, 2017

Answer:

69g of #CO_2#

Explanation:

Ethane's formula is #C_2H_6#. These products and reactants are common in combustion reactions, below is the balanced reaction. This is the key to solving this problem.

#2C_2H_6+7O_2 to 6H_2O+ 4CO_2#

The question tells us #C_2H_6# is the excess reactant, thus #O_2# is the limiting reactant.

#88g((O_2)/(32g))((4CO_2)/(7O_2))((44.01g)/(CO_2)) = 69g#