# How many grams of CO_2 are produced when 88 g of O_2 are reacted with an excess of ethane?

Jun 24, 2017

69g of $C {O}_{2}$

#### Explanation:

Ethane's formula is ${C}_{2} {H}_{6}$. These products and reactants are common in combustion reactions, below is the balanced reaction. This is the key to solving this problem.

$2 {C}_{2} {H}_{6} + 7 {O}_{2} \to 6 {H}_{2} O + 4 C {O}_{2}$

The question tells us ${C}_{2} {H}_{6}$ is the excess reactant, thus ${O}_{2}$ is the limiting reactant.

$88 g \left(\frac{{O}_{2}}{32 g}\right) \left(\frac{4 C {O}_{2}}{7 {O}_{2}}\right) \left(\frac{44.01 g}{C {O}_{2}}\right) = 69 g$