# How many grams of copper (II) chloride should be added to 1.50 Liters of water if a 2.235 M solution is desired?

Jan 10, 2017

$\text{Approx. 1/2 kilo of copper(II) sulfate}$.

#### Explanation:

$\text{Concentration}$ $=$ $\text{Moles of solute"/"Volume of solution}$.

$\text{Moles of solute"="Concentration"xx"Volume of solution}$

$2.235 \cdot m o l \cdot \cancel{{L}^{-} 1} \times 1.50 \cdot \cancel{L} = 3.3525 \cdot m o l$.

"Mass of cupric chloride "=3.3525*cancel(mol)xx134.45 *g*cancel(mol^-1)=??*g