How many grams of MgSO_4 are needed to prepare 125mL 0.200M magnesium sulfate?

Mar 1, 2017

$\text{Concentration}$ $=$ $\text{Moles of solute"/"Volume of solution}$

Explanation:

And $\text{mass of solute "=" moles"xx"molar mass}$

And so we calculate the product:

$\text{Volume"xx"Concentration"xx"Molar mass of magnesium sulfate}$

$= 125 \times {10}^{-} 3 \cancel{L} \times 0.200 \cdot \cancel{m o l \cdot {L}^{-} 1} \times 120.37 \cdot g \cdot \cancel{m o {l}^{-} 1}$, an answer with units of mass as required.

=??*g