How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? Na2O + H2O ---> 2 NaOH

1 Answer
Jul 1, 2014

This is a typical stoichiometry question.To answer this question you want to get a relationship between #Na_2#O and NaOH.

So you can get a relationship between the moles of #Na_2#O
and moles of NaOH by the concept of stoichiometry.

#Na_2#O + #H_2#O ----------------> 2 NaOH.

According to above balanced equation we can have the stoichiometry relationship between #Na_2#O and NaOH. as 1:2

It means 1 moles of #Na_2#O is required to react with one mol of #H_2#O to produce 2 moles of NaOH.

in terms of mass 1 mole of #Na_2#O has mass 62 g on reaction with water produces 2 moles of NaOH or 80 g of NaOH.

62 g of #Na_2#O produces 80 g of NaOH.

1g of NaOH is produced from 62/80 g of #Na_2#O

1.6 x #10^2# g of NaOH will require 62 x 1.6 x #10^2# g / 80 of #Na_2#O

124g of #Na_2#O.