# How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? Na2O + H2O ---> 2 NaOH

Jul 1, 2014

This is a typical stoichiometry question.To answer this question you want to get a relationship between $N {a}_{2}$O and NaOH.

So you can get a relationship between the moles of $N {a}_{2}$O
and moles of NaOH by the concept of stoichiometry.

$N {a}_{2}$O + ${H}_{2}$O ----------------> 2 NaOH.

According to above balanced equation we can have the stoichiometry relationship between $N {a}_{2}$O and NaOH. as 1:2

It means 1 moles of $N {a}_{2}$O is required to react with one mol of ${H}_{2}$O to produce 2 moles of NaOH.

in terms of mass 1 mole of $N {a}_{2}$O has mass 62 g on reaction with water produces 2 moles of NaOH or 80 g of NaOH.

62 g of $N {a}_{2}$O produces 80 g of NaOH.

1g of NaOH is produced from 62/80 g of $N {a}_{2}$O

1.6 x ${10}^{2}$ g of NaOH will require 62 x 1.6 x ${10}^{2}$ g / 80 of $N {a}_{2}$O

124g of $N {a}_{2}$O.