# How many grams of solute a contained in 2.5 liters of 3.0 molar aluminum nitrate solution?

Jun 4, 2017

Approx. $1.6 \cdot k g$ of solute............

#### Explanation:

$\text{Concentration"="Moles of solute"/"Volume of solution}$

And so to get the $\text{moles of solute}$, we take the product........

$\text{concentration"xx"volume} = 3.0 \cdot m o l \cdot \cancel{{L}^{-} 1} \times 2.5 \cdot \cancel{L} = 7.5 \cdot m o l .$

And to get the mass of $\text{aluminum nitrate}$ we take the product,

"Molar quantity"xx"molar mass"=7.5*molxx213.03*g*mol^-1=??*g