How many grams of solute a contained in 2.5 liters of 3.0 molar aluminum nitrate solution?

1 Answer
Jun 4, 2017

Answer:

Approx. #1.6*kg# of solute............

Explanation:

#"Concentration"="Moles of solute"/"Volume of solution"#

And so to get the #"moles of solute"#, we take the product........

#"concentration"xx"volume"=3.0*mol*cancel(L^-1)xx2.5*cancel(L)=7.5*mol.#

And to get the mass of #"aluminum nitrate"# we take the product,

#"Molar quantity"xx"molar mass"=7.5*molxx213.03*g*mol^-1=??*g#