# How many milliliters of water are needed to make a 0.171 M solution that contains 1.00 g of NaCl?

May 14, 2017

$100. m L$

#### Explanation:

You will be using the basic molarity equation, but first, we must convert the grams of $N a C l$ to moles:

$1.00 g N a C l \left(\frac{1 m o l N a C l}{58.44 g N a C l}\right) = 0.0171 m o l N a C l$

Now, we'll use the molarity equation

$M = \frac{m o l s o l u t e}{L s o \ln}$

and solve for volume ($L$):

$L s o \ln = \frac{m o l s o l u t e}{M}$

and plug in known variables to find the volume

$L s o \ln = \frac{0.0171 m o l}{0.171 \frac{m o l}{L}} = 0.100 L$

Lastly, we'll convert from liters to milliliters:

$\left(0.100 L\right) \frac{1000 m L}{1 L} = 100. m L$