Question

How many mL of a 0.100 M solution are required have `1.32 x 10^2` moles of solute?

Answer 1

Rather a large volume, over `1*m^3`

Explanation:

`"Concentration"` `=` `"Moles of solute"/"Volume of solution"`.

And, typically, `"concentration"` has units of `mol*L^-1`.

Here, clearly, `"Volume of solution"="Moles of solute"/"Concentration"`

`=(1.32xx10^2*mol)/(0.100*mol*L^-1)=1320*L`