How many molecules are present in 1.0 x 103g of water? (Answer with correct number of sig figs)

1 Answer
Nov 14, 2016

Answer:

#"Number of water molecules"#
#= (1.0xx10^3*g)/(18.01*g*mol^-1)xx6.022xx10^23*mol^-1#

Explanation:

We use #"Avogadro's number"# #=# #6.022 xx 10^23 *mol"^-1#.

And since the units clearly cancel out we get the answer as a dimensionless number.

I leave it to you to determine the correct number of significant figures.