# How many moles of gas are in a volume of 63.3 L at STP?

##### 1 Answer

#### Answer:

At STP of 273.15 K and 100 kPa, 63.3 L of an ideal gas would contain 2.33 moles.

At STP of 273.15 K and 1 atm, 63.3 L of an ideal gas would contain 2.82 moles.

#### Explanation:

At STP of 273.15 K

In order to answer this question, divide the given volume by the molar volume of 27.710980 L/mol.

https://en.m.wikipedia.org/wiki/Molar_volume

Just in case your teacher uses the older values for STP, 273.15 K and 1 atm. The molar volume of a gas at this STP is 22.414 mol/L.

https://en.m.wikipedia.org/wiki/Molar_volume

Just as with the previous calculation, divide the given volume by the molar volume of 22.414 mol/L.