# How many moles of HCl are required to completely neutralize 0.30 moles of Ca(OH)_2?

Nov 25, 2017

Why $0.60 \cdot m o l$....

#### Explanation:

And how do we know?

Well, we interrogate the stoichiometric equation...

$C a {\left(O H\right)}_{2} \left(s\right) + 2 H C l \left(a q\right) \rightarrow C a C {l}_{2} \left(a q\right) + 2 {H}_{2} O \left(l\right)$

Two equiv of $H C l$ are required per equiv $\text{calcium hydroxide}$..

What number of $H C l$ molecules are required for equivalence?