How many moles of solute is contained in 1.75 L of 0.215 M solution?

1 Answer
Feb 16, 2017

Answer:

#"Concentration"# #=# #"Moles of solute"/"Volume of solution"#

#"approx. " 0.4*mol#

Explanation:

Given the above, #"Moles of solute"# is given by the PRODUCT:

#"Concentration "xx" Volume of solution"# #=#

#=0.215*mol*cancel(L^-1)xx1.75*cancelL=??*mol#

Clearly, this answer is consistent dimensionally. Why so?