How many moles of solute is contained in 250mL of 0.300 M solution?

1 Answer
Oct 31, 2016

#0.0750*mol# of solute are present.

Explanation:

#"Concentration"# #=# #"Moles of solute"/"Volume of solution"#, and typically the units of concentration are #mol*L^-1#.

So if we want to access the moles of solute, we take the product:

#"Concentration"xx"Volume of solution"#.

Here, #0.300*mol*cancel(L^-1)xx0.250*cancelL=??mol#, and cancellation of units gives us an answer in #"moles"# as required. This is an example of dimensional analysis. It would be all too simple to multiply instead of divide or vice versa; we have all done it. If you do such problems dimensionally, this is an extra check on the solution to your problem.