# How many moles of solute is contained in 250mL of 0.300 M solution?

Oct 31, 2016

$0.0750 \cdot m o l$ of solute are present.

#### Explanation:

$\text{Concentration}$ $=$ $\text{Moles of solute"/"Volume of solution}$, and typically the units of concentration are $m o l \cdot {L}^{-} 1$.

So if we want to access the moles of solute, we take the product:

$\text{Concentration"xx"Volume of solution}$.

Here, 0.300*mol*cancel(L^-1)xx0.250*cancelL=??mol, and cancellation of units gives us an answer in $\text{moles}$ as required. This is an example of dimensional analysis. It would be all too simple to multiply instead of divide or vice versa; we have all done it. If you do such problems dimensionally, this is an extra check on the solution to your problem.