How many moles of Sr(NO_3)_2 would be used in the preparation of 2.50 L of a 3.5 M solution?

Jan 14, 2018

$\eta = 8.8 \text{ mol of } S r \left(N {O}_{3}\right) 2$

Explanation:

The problem can be directly solved using the standard formula

"Molarity"(M)=(("number of moles")(eta))/(("Liter solution")(V), so that

$\eta = \left(M\right) \times \left(V\right)$

$\eta = \frac{3.5 m o l}{\cancel{L}} \times 2.50 \cancel{L}$

$\eta = 8.8 m o l$