# How many mols of H_2SO_4 will neutralize 78.3 mK of 0.187 N NaOH?

Dec 21, 2016

See below.

#### Explanation:

For this calculation, I'm assuming you meant 78.3 mL (not "mK") and 0.187M NaOH (basically that you made two major typos, since both K and N are close together to letters l and M which would make sense on a standardized keyboard).

If that is the case, and the units are not arbitrary, then the calculation should be correct. If it's not then I'm sorry as this is the best I could do with the information provided.

If this is the type of question you are trying to answer, remember to always start with a balanced chemical equation. The chemical system in question must be balanced to perform the calculation.

In our case:

${H}_{2} S {O}_{4} + 2 N a O H \to 2 {H}_{2} O + N {a}_{2} \left(S {O}_{4}\right)$

and

Consider the graphic below: