How much calcium hydroxide (Ca(OH)_2), in grams, is needed much produce 1.5 L of a 0.25M solution?

Apr 8, 2017

27.75 gm

Explanation:

molarity is defined as = moles of solute / litres of solution

to produce 1.5 L of 0.25 M solution ,
moles of calcium hydroxide needed are = $0.25 \cdot 1.5$
= 0.375 mol
now amount of calcium hydroxide in grams needed can be calculated by multiplying moles by molar mass : $0.375 \cdot 74$
= 27.75 gm