# How much energy, in kilojoules, are released or absorbed from the reaction of 1 mole of N_2, nitrogen, with 3 moles of molecular hydrogen, H_2, to form 2 moles of ammonia, NH_3?

Mar 25, 2018

So you want the enthalpy associated with the reaction....

#### Explanation:

${N}_{2} \left(g\right) + 3 {H}_{2} \left(g\right) \rightarrow 2 N {H}_{3} \left(g\right) + \Delta$

And so we got.....

$\Delta {H}_{\text{rxn}}^{\circ} = 2 \times \Delta {H}_{f}^{\circ} N {H}_{3} \left(g\right) = 2 \cdot m o l \times - 46 \cdot k J \cdot m o {l}^{-} 1 = - 92 \cdot k J .$

Of course $\Delta {H}_{f}^{\circ} N {H}_{3} \left(g\right)$ is the enthalpy associated with ONE MOLE of ammonia....