Question

How much energy, in kilojoules, are released or absorbed from the reaction of 1 mole of `N_2`, nitrogen, with 3 moles of molecular hydrogen, `H_2`, to form 2 moles of ammonia, `NH_3`?

Answer 1

So you want the enthalpy associated with the reaction....

Explanation:

`N_2(g) +3H_2(g) rarr 2NH_3(g)+Delta`

And so we got.....

`DeltaH_"rxn"^@=2xxDeltaH_f^@NH_3(g)=2*molxx-46*kJ*mol^-1=-92*kJ.`

Of course `DeltaH_f^@NH_3(g)` is the enthalpy associated with ONE MOLE of ammonia....