Question

How much energy is absorbed if 5 kg of aluminum is heated from 10-20 degrees C? (c of aluminum is 900 J/Kg)?

Answer 1

`4.5*10^4 kJ`

Explanation:

`q = (5*10^3g)*10°C*900J/(g*°C) = 4.5*10^7J = 4.5*10^4 kJ`

This assumes constant pressure, which is a reasonable assumption given the relative constancy of atm.