# How much energy is needed to melt 250 grams of ice at 0 C?

Dec 21, 2017

You need to quote the $\text{latent heat of fusion of water....}$

#### Explanation:

And you will get a value in $J \cdot {g}^{-} 1$...and then you can assess the energy required for the transition....

H_2O(s) stackrel(Delta, 0""^@C)rarrH_2O(l)

Both the ice and the water are assumed to be at $0$ ""^@C...of course, if different temperatures are specified you will need the heat capacities of ice, and of liquid water...

Dec 21, 2017

$Q = 83.5 k J$

#### Explanation:

To answer to this question, you need the equation:

$Q = {L}_{\text{ice}} \times m$

$Q$ is the amount of heat needed to melt the ice, ${L}_{\text{ice}}$ is the Latent Heat of melting for ice, and $m$ is the given mass of ice. Various tables of latent heats give us:

L_(ice)=3.34 · 10^5 J/(kg)

$m = 250 g = 0.25 k g$.

So:

Q=(3.34 · 10^5 J/(kg)) xx (0.25 " kg")=83,500J=83.5kJ