How much energy is needed to melt 250 grams of ice at 0 C?

2 Answers
Dec 21, 2017

Answer:

You need to quote the #"latent heat of fusion of water...."#

Explanation:

And you will get a value in #J*g^-1#...and then you can assess the energy required for the transition....

#H_2O(s) stackrel(Delta, 0""^@C)rarrH_2O(l)#

Both the ice and the water are assumed to be at #0# #""^@C#...of course, if different temperatures are specified you will need the heat capacities of ice, and of liquid water...

Dec 21, 2017

Answer:

#Q=83.5kJ#

Explanation:

To answer to this question, you need the equation:

#Q=L_"ice"xxm#

#Q# is the amount of heat needed to melt the ice, #L_"ice"# is the Latent Heat of melting for ice, and #m# is the given mass of ice. Various tables of latent heats give us:

#L_(ice)=3.34 · 10^5 J/(kg)#

#m=250g=0.25kg#.

So:

#Q=(3.34 · 10^5 J/(kg)) xx (0.25 " kg")=83,500J=83.5kJ#