# How much heat must be removed to freeze a tray of ice cubes at 0°C if the water has a mass of 225 g?

Jul 16, 2018

It will require the removal of $\text{75200 J}$ of energy.

#### Explanation:

Use the heat of fusion equation:

$q = m \cdot {H}_{\text{f}}$,

where:

$q$ is the amount of energy, $m$ is mass in grams, and ${H}_{\text{f}}$ is the heat of fusion.

Known

$\text{mass", m="225 g}$

$\text{heat of fusion of water", H_"f"="334 J/g}$

Unknown

$\text{energy removed", q}$

Solution

Plug in the known values and solve.

q=225color(red)cancel(color(black)("g"))xx(334"J")/(1color(red)cancel(color(black)("g")))="75200 J" rounded to three significant figures