How much heat must be removed to freeze a tray of ice cubes at 0°C if the water has a mass of 225 g?

1 Answer
Jul 16, 2018

Answer:

It will require the removal of #"75200 J"# of energy.

Explanation:

Use the heat of fusion equation:

#q=m*H_"f"#,

where:

#q# is the amount of energy, #m# is mass in grams, and #H_"f"# is the heat of fusion.

Known

#"mass", m="225 g"#

#"heat of fusion of water", H_"f"="334 J/g"#

Unknown

#"energy removed", q"#

Solution

Plug in the known values and solve.

#q=225color(red)cancel(color(black)("g"))xx(334"J")/(1color(red)cancel(color(black)("g")))="75200 J"# rounded to three significant figures