# How much is 325 F. in °C?

Sep 9, 2015

${325}^{\circ} F = 162 \frac{7}{9} {\textcolor{w h i t e}{\text{X}}}^{\circ} C$

#### Explanation:

Boiling point of water is ${212}^{\circ} F = {100}^{\circ} C$
Freezing Point of water is ${32}^{\circ} F = {0}^{\circ} C$
Difference between boiling and freezing is $180 {F}^{\circ} = 100 {C}^{\circ}$

${325}^{\circ} F$ is $325 - 32 = 293 {F}^{\circ}$ above freezing

$293 {F}^{\circ} \times \frac{100 {C}^{\circ}}{180 {F}^{\circ}} = 162 \frac{7}{9} {C}^{\circ}$

${325}^{\circ} F$ is $162 \frac{7}{9} {C}^{\circ}$ above freezing or $162 \frac{7}{9} {\textcolor{w h i t e}{\text{X}}}^{\circ} C$