# How much momentum does a 1/2 kg object moving at 64 ms^-1 have?

Kinetic energy is just given by ${E}_{k} = \frac{1}{2} m {v}^{2}$. In this case, ${E}_{k} = \frac{1}{2} \cdot \frac{1}{2} \cdot {64}^{2} = 1024$ $J$
Not too much more to explain for this question. Kinetic energy is the energy something has because it has mass and is in motion, and is calculated using the equation ${E}_{k} = \frac{1}{2} m {v}^{2}$, where ${E}_{k}$ is the kinetic energy $\left(J\right)$, $m$ is the mass $\left(k g\right)$ and $v$ is the velocity $\left(m {s}^{-} 1\right)$.