How much work would it take to push a # 6 kg # weight up a # 12 m # plane that is at an incline of # pi / 4 #?

1 Answer
Apr 2, 2016

Answer:

51 Joules

Explanation:

Here,
Hypotenuse (h) = 12m
Angle of inclination (#theta#)= π/4
Perpendicular (p) = ?

We have, # Sin theta = p/h #
or, # Sin (π/4) = p/12 #
or, # p = 12/sqrt(2) #
Hence, p = 8.5 m, which is the distance travelled.

Since work(W) is given by
W = F * S,
Where F = Force ( here weight) = 6 kg wt = 6 N
(Note kg wt, unlike kg, is same as Newton and is a unit of weight, not mass).
S is the distance traveled given by the perpendicular 8.5m
Therefore,
#W = 6 * 8.5 = 51 "Joules"#