How much would #4.2 * 10^23# molecules of #KSO_4# weigh in grams?

1 Answer
Aditya Banerjee.
Nov 14, 2016

Answer is 94.139 grams.

Explanation:

According to Avogadro's law,
#6.023xx10^23# molecules of #KSO_4# weigh 135 grams.

#:.4.2xx10^23# molecules of #KSO_4# weigh #(135)/(6.023xx10^23)xx(4.2xx10^23)# grams,i.e. #94.139# grams. (Answer).

Related questions
See all questions in The Mole
Impact of this question
1354 views around the world
You can reuse this answer
Creative Commons License