# How to convert between the am u\ m^2\ s^-2  into {kJ}/g?

## Calculate the energy produced from the fusion of Deuterium and Tritium into Helium and a neutron, in kJ per gram of Deuterium used. Please help! I don't know how to convert from $a m u \setminus {m}^{2} \setminus {s}^{-} 2$ into $\frac{k J}{g}$. Also, do I need to do anything further if they say "in kJ per gram of Deuterium used"?

Dec 24, 2017

${10}^{-} 6 \frac{k J}{g}$

#### Explanation:

Because 1 J = $k g {m}^{2} / {s}^{2} \mathmr{and} 1 k J = {10}^{3} J$
${m}^{2} / {s}^{2} = \frac{J}{k g} = \frac{{10}^{-} 3 k J}{{10}^{3} g}$

Thus,

${m}^{2} / {s}^{2} = {10}^{-} 6 \frac{k J}{g}$