Question

How to find in which quadrant the equation of a line `12x+5y-10=0` lies?

Answer 1

Change the equation into the y-intercept gradient form first.

`y = mx+c`

`5y = -12x+10`

`y = -12/5x +2`

The y-intercept is `+2` and the slope is negative which means the line will rise to the left.

The line will pass through the `2nd, 1st and 4th` quadrants. graph{y = -12/5x+2 [-5.75, 4.25, -1.7, 3.3]}