How to find in which quadrant the equation of a line 12x+5y-10=012x+5y10=0 lies?

1 Answer
Sep 17, 2017

Change the equation into the y-intercept gradient form first.

y = mx+cy=mx+c

5y = -12x+105y=12x+10

y = -12/5x +2y=125x+2

The y-intercept is +2+2 and the slope is negative which means the line will rise to the left.

The line will pass through the 2nd, 1st and 4th 2nd,1stand4th quadrants. graph{y = -12/5x+2 [-5.75, 4.25, -1.7, 3.3]}