How to find the asymptotes of #f(x) = (x^2-1)/(2x^2 + 3x-2)#?

1 Answer
Dec 25, 2015

Answer:

-2 and -1/2 are the asymptotes

Explanation:

To find the asymptotes of an equation, think of values that cannot be a result of the function when it is substituted by many values.

In this case, since it is a fraction, 0 denominator is not possible cpbecause it will lead to undefine , so to find the asymptotes, find values that could make the denominator.

So let # 2x^2 + 3x -2=0#

Then solve for x

# 2x^2 + 3x -2=0#
# (2x-1)(x+2)=0#
#2x-1=0#
#x=1/2#
And

#x+2=0#
#x=-2#

So the asymptotes are -2 and #1/2#