# How to find the range, variance, and standard deviation of these numbers; 2,489; 48,430; 51,840; 53,179; 65,755; 268,581?

Variance( ${\sigma}^{2}$) : for this you need to calculate the average. $\overline{x} =$81,72
${\sigma}^{2} = \frac{{\left({x}_{1} - \overline{x}\right)}^{2} + \ldots {\left({x}_{n} - \overline{x}\right)}^{2}}{N}$ , where N is the number of data you have.
The standard deviation ( $\sigma$) is the square root of the variance.